The balanced chemical equation for the reaction of CoCl 2 (iPrOH) 2 with methanol (MeOH) in Task1 is: CoCl 2 (iPrOH) 2 + 4 MeOH – – CoCl 2 (MeOH) 4…

The balanced chemical equation for the reaction of CoCl2(iPrOH)2 with methanol (MeOH) in Task1 is:

CoCl2(iPrOH)2  +  4 MeOH  -> <-  CoCl2(MeOH)4  +  2 iPrOH

If 3.00 mL of 0.0103 M CoCl2(iPrOH)2 is combined with 1.00 mL of MeOH at room temperature (25 °C), and at equilibrium the mixture gives an absorbance of 0.705 at λmax= 656 nm, determine the product CoCl2(MeOH)4 concentration (in M) at equilibrium and the ratio [CoCl2(MeOH)4] / [CoCl2(iPrOH)2] at equilibrium. For these calculations assume the temperature remains constant at 25 °C. There are four steps here. First the initial concentration of CoCl2(iPrOH)2 needs to be determined. Second, the equilibrium concentration of CoCl2(iPrOH)2 must be found. Third is the calculation of the equilibrium concentration of CoCl2(MeOH)4, then fourth, the ratio [CoCl2(MeOH)4] / [CoCl2(iPrOH)2] at equilibrium. Show all work. Remember to state the equations you are using defining all variables and constants. Then substitute in the values and show the results. Be certain all sig figs and units are correct. You are expected to follow this format in all subsequent lab work without being prompted.

Let V(CoCl2(EtOH)2/MeOH) = V1; V(CoCl2(iPrOH)2/MeOH) = V2;The total volume is V1+V2 = 3.00 mL;The number of data rows in a table is 5.The first is V1 = 2.00 mL; V2 = 1.00 mL;The last is V1 =…