When 0.105 mol propane is burned in an excess of oxygen, how many moles of oxygen are consumed? The reaction is C3H8 + 5 O2 ?

When 0.105 mol propane is burned in an excess of oxygen, how many moles of oxygen are consumed? The reaction is C3H8 + 5 O2 ? mol O2 = 0.105 mol C3H8 How many grams of nitric acid are produced for every 100.0 g NO2 that reacts?

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