A) Combining0.253molFe2O3with excess carbon produced18.8gFe. Fe2O3+3C2Fe+3CO What is the actual yield of iron inmoles? What is the theoretical yield

A) Combining 0.253 mol Fe2O3 with excess carbon produced 18.8 g Fe.

Fe2O3+3C⟶2Fe+3CO

What is the actual yield of iron in moles?

What is the theoretical yield of iron in moles?

What is the percent yield of iron in moles?

B) Assuming an efficiency of 20.80%, calculate the actual yield of magnesium nitrate formed from 137.0 g of magnesium and excess copper(II) nitrate.

Mg+Cu(NO3)2⟶Mg(NO3)2+Cu

C) Each step in the process CH4+4Cl2⟶CCl4+4HCl

CCl4+2HF⟶CCl2F2+2HCl

has a yield of 90.0%. The CCl4 formed in the first step is used as a reactant in the second step.

If 9.00 mol of CH4 reacts, what is the total amount of HCl produced? Assume that Cl2 and HF are present in excess.

D) For each reaction, identify the precipitate, or lack thereof.

CaCl2(aq)+K2CO3(aq)⟶CaCO3+2KCl

FeCl2(aq)+(NH4)2SO4(aq)⟶FeSO4+2NH4Cl

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