The oak tree pathogen Phytophthora ramorum has migrated 650 km in ten years. West Nile virus spread from New York State to 46 others states in five years. The difference in the rate of spread is probably related to
In its resting state, the membrane surrounding a neuron is permeable to potassium ions but not permeable to sodium ions. Thus, positive K ions can flow through the membrane in an attempt to equalize K concentration, but Na ions cannot. This leads to an excess of Na ions outside of the cell. If the space outside the cell is defined as zero electric potential, then the electric potential of the interior of the cell is negative. This resting potential is typically about -80 rm mV. A schematic of this situation is shown in the figure.
Vinegar, which is just a dilute acetic acid solution, is very common and versatile. The concentration of store-bought vinegar is 5.0 % solution by mass, and its density is approximately 1.01 g/mL.
(a) Determine the molarity of acetic acid in vinegar.
(b) If I use 2 cups (473.2 mL) of vinegar from part (a) to help create a cleaning solution for my windows, how many molecules of acetic acid is this?
(c) How many atoms of carbon are in 2 cups of this new vinegar you made in part (a)?
All work must be shown, labeled, and explained in detail to receive credit. Note that superscripts (X2) can be written as X^2 and subscripts (X2) can be written as X_2 if it saves you time. Be careful to account for significant figures in your final answers.
an astronaut in her space suit has a total mass of 87 kg, including suit and oxygen tank. Her tether line loses its attachment to her spacecraft while she’s on a spacewalk. Initially at rest with respect to her spacecraft,she throws her 12 kg oxygen tank away from her spacecraft with a speed of 8m/s to propel herself back toward it (a)determine the maximaum distance she can be from the craft and still return with 2 min(b)explain in terms of newton’s laws of motion why this strategy works.
The balanced chemical equation for the reaction of CoCl2(iPrOH)2 with methanol (MeOH) in Task1 is:
CoCl2(iPrOH)2 + 4 MeOH -> <- CoCl2(MeOH)4 + 2 iPrOH
If 3.00 mL of 0.0103 M CoCl2(iPrOH)2 is combined with 1.00 mL of MeOH at room temperature (25 °C), and at equilibrium the mixture gives an absorbance of 0.705 at λmax= 656 nm, determine the product CoCl2(MeOH)4 concentration (in M) at equilibrium and the ratio [CoCl2(MeOH)4] / [CoCl2(iPrOH)2] at equilibrium. For these calculations assume the temperature remains constant at 25 °C. There are four steps here. First the initial concentration of CoCl2(iPrOH)2 needs to be determined. Second, the equilibrium concentration of CoCl2(iPrOH)2 must be found. Third is the calculation of the equilibrium concentration of CoCl2(MeOH)4, then fourth, the ratio [CoCl2(MeOH)4] / [CoCl2(iPrOH)2] at equilibrium. Show all work. Remember to state the equations you are using defining all variables and constants. Then substitute in the values and show the results. Be certain all sig figs and units are correct. You are expected to follow this format in all subsequent lab work without being prompted.
Let V(CoCl2(EtOH)2/MeOH) = V1; V(CoCl2(iPrOH)2/MeOH) = V2;The total volume is V1+V2 = 3.00 mL;The number of data rows in a table is 5.The first is V1 = 2.00 mL; V2 = 1.00 mL;The last is V1 =…
A 27 pound meteorite struck a car, leaving a dent 26 cm deep in the trunk. If the meteorite struck the car with a speed of 620 m/s, what was the magnitude of its deceleration, assuming it to be constant?
In a slow-pitch softball game, a 0.200 kg softball crossed the plate at 17.0 m/s at an angle of 35.0° below the horizontal. The batter hits the ball toward center field, giving it a velocity of 46.0 m/s at 30.0° above the horizontal.(a) Determine the impulse delivered to the ball.1Your response differs from the correct answer by more than 10%. Double check your calculations. N·s (magnitude)2Your response differs from the correct answer by more than 10%. Double check your calculations.° (above the horizontal)(b) If the force on the ball increases linearly for 4.00 ms, holds constant for 20.0 ms, then decreases linearly to zero in another 4.00 ms, what is the maximum force on the ball?3 N (magnitude)4° (above the horizontal)
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