The following information is given for tin at 1 atm: boiling point = 2.27010 3 CH vap ( 2.27010 3 C) = 1.93910 3 J/gmelting point = 232.0 CH fus (…

tin

boiling point = 2.270×103 °CHvap(2.270×103 °C) = 1.939×103 J/gmelting point = 232.0 °CHfus(232.0 °C) = 59.60 J/gspecific heat solid = 0.2260 J/g°Cspecific heat liquid = 0.2430 J/g°C

46.70tin638.027.0Report the answer as a positive number.

_______ kJ

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