The position of a squirrel running in a park is given by r=[(0.280m/s)t+(0.0360m/s^2)t^2]+(0.0190m/s^3)t^3. a.At 5.87 , how far is the squirrel from

The position of a squirrel running in a park is given by r=[(0.280m/s)t+(0.0360m/s^2)t^2]+(0.0190m/s^3)t^3.a.At 5.87 , how far is the squirrel from its initial position?b.At 4.31 , what is the magnitude of the squirrel’s velocity?c.At 4.31 , what is the direction (in degrees counterclockwise from +x-axis) of the squirrel’s velocity?